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4v^2-10v-66=0
a = 4; b = -10; c = -66;
Δ = b2-4ac
Δ = -102-4·4·(-66)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-34}{2*4}=\frac{-24}{8} =-3 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+34}{2*4}=\frac{44}{8} =5+1/2 $
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